Difference between revisions of "ListXneqY"

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m
m (<lsl> tag to <source>)
 
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See also: [[List|Lists]]
See also: [[List|Lists]]


<lsl>
<source lang="lsl2">
integer ListXneqY(list lx, list ly)
integer ListXneqY(list lx, list ly)
{
{
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     return TRUE;
     return TRUE;
}
}
</lsl>
</source>


Example:<br />
Example:<br />


<lsl>
<source lang="lsl2">
list l1 = ["a","b","c","d", 1,2];
list l1 = ["a","b","c","d", 1,2];
list l2 = ["a",1,"b",2,"c",3,"d"];
list l2 = ["a",1,"b",2,"c",3,"d"];
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   }
   }
}
}
</lsl>
</source>


</div>
</div>

Latest revision as of 15:24, 22 January 2015

Function: integer ListXneqY(list lx, list ly);

Answers the question: is list X different from list Y?

Returns the number 1 if true, 0 if false

Note: requires also the function ListXnotY .

The opposite function is ListXequY .

See also: Lists

integer ListXneqY(list lx, list ly)
{
    if(lx == ly)
        return !(ListXnotY(lx,ly) == []);
    return TRUE;
}

Example:

list l1 = ["a","b","c","d", 1,2];
list l2 = ["a",1,"b",2,"c",3,"d"];
 
integer ListXneqY(list lx, list ly)
{
    if(lx == ly)
        return !(ListXnotY(lx,ly) == []);
    return FALSE;
}
 
list ListXnotY(list lx, list ly)
{// return elements in X list that are not in Y list
    list lz;
    integer n = llGetListLength(lx);
    while(n--)
	if ( !~llListFindList(ly,llList2List(lx,n,n)) )
	    lz += llList2List(lx,n,n);
    return lz;
}

default{
   state_entry() {
      llSay(0, "Are we different lists? " + (string)ListXneqY(l1,l2));
      //will say in this example: 1 , meaning yes.
   }
}

Posted with the kind permission of Very Keynes, who originated this script June 2007 in the SL scripters forum http://forums-archive.secondlife.com/54/e4/194138/1.html