Difference between revisions of "LlListSort"

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===Utilizing the Results===
 
===Utilizing the Results===
  
It's important to note that the source list that you are sorting will remain unchanged. Instead, a new, sorted list will be produced. So, it's important that you capture this with a variable (unless you are acting directly on the results.
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It's important to note that the source list that you are sorting will remain unchanged. Instead, a new, sorted list will be produced. So, it's important that you capture this with a variable (unless you are acting directly on the results.)
  
 
<lsl>llListSort(myList,1,TRUE); // you've wasted cpu time; you didn't capture the results<br />
 
<lsl>llListSort(myList,1,TRUE); // you've wasted cpu time; you didn't capture the results<br />

Revision as of 15:18, 14 July 2008

Summary

Function: list llListSort( list src, integer stride, integer ascending );

Returns a list that is src sorted by stride.

• list src List to be sorted.
• integer stride number of entries per stride, if less then 1 it is assumed to be 1.
• integer ascending if FALSE then the sort order is descending, otherwise the order is ascending.

This function supports Strided Lists.

Specification

A slow bubble sort is employed to perform the sort.
The sort order is affected by type.
Each type is sorted individually and then feathered to have the same order of types. <lsl>llListSort([1, "C", 3, "A", 2, "B"], 1, TRUE) returns [1, "A", 2, "B", 3, "C"] llListSort([1, 3, 2, "C", "A", "B"], 1, TRUE) returns [1, 2, 3, "A", "B", "C"]

llListSort([1, "C", 3, "A", 2, "B"], 2, TRUE) returns [1, "C", 2, "B", 3, "A"]</lsl>

Caveats

A bubble sort is a sorting algorithm with a Big O of N*N. Why Linden Labs did not use a N*log(N) sorting algorithm such as Heap Sort or Merge Sort is unkown...

All Issues ~ Search JIRA for related Bugs

Examples

<lsl> list numbers = [3, "three", 2, "two", 1, "one"]; default {

   state_entry()
   {
       llOwnerSay(llDumpList2String(numbers, ","));
       // Object: 3,three,2,two,1,one
       numbers = llListSort(numbers, 2, TRUE);
       llOwnerSay(llDumpList2String(numbers, ","));
       // Object: 1,one,2,two,3,three
   }

}

</lsl>

Notes

Data Types

llListSort really only works on items of the same type. It will work on lists that hold diverse data types -- to be clear, it won't blow up your script -- but the results returned are usually meaningless.

<lsl>list mylist = ["brown", <0.000000, 0.000000, 0.000000>, "house", 17.005, 100, "cat", <3.000000, 3.000000, 3.000000>, 39]; list tmplist = llListSort(mylist,1,TRUE); llSay(0, llList2CSV(tmplist));</lsl>

This returns in chat:

brown, <0.000000, 0.000000, 0.000000>, cat, 17.004999, 39, house, <3.000000, 3.000000, 3.000000>, 100

Utilizing the Results

It's important to note that the source list that you are sorting will remain unchanged. Instead, a new, sorted list will be produced. So, it's important that you capture this with a variable (unless you are acting directly on the results.)

<lsl>llListSort(myList,1,TRUE); // you've wasted cpu time; you didn't capture the results
list newlist = llListSort(myList,1,TRUE);//okay. You've captured the results.
llSay(0,llList2CSV(llSortList(myList,1,TRUE))); //no need to capture, using the results right away.</lsl>

Stride parameter

Most times, you will want to set "integer stride" to 1 (0 also works) to tell it to sort each item in the list on its own basis. (If you are working with a strided list, though, see the special section below on sorting strides.)

Sort Order

Setting the parameter "integer ascending" to TRUE returns a sorted list that is in ascending order.
For example: ["Apples", "Bananas", "Oranges"]

Setting the parameter "integer ascending" to FALSE returns a sorted list that is in descending order.
For example: ["Oranges", "Bananas", "Apples"]

Sorting Strided Lists

If you have a strided list, in which you are keeping related pieces of data together in chunks, letting each list element sort on its own basis would be disastrous.

<lsl>list demographics = ["John Adams", "male", "2007-06-22", "Shirley Bassey", "female", "2005-11-02", "Matt Damon", "male", "2008-05-19"];</lsl>

Bad Example

<lsl>list tmplist_1 = llListSort(demographics, 1, TRUE); //tmplist_1 == ["2005-11-02", "2007-06-22", "2008-05-19", "John Adams", "Matt Damon", "Shirley Bassey", "female", "male", "male"] //The strides have been destroyed, the sorted data is no useless</lsl>

Good Example

Instead, because you have the data grouped (aka "strided") in sets of 3, you need to do this:

<lsl>list tmplist_2 = llListSort(demographics,3,TRUE); //templist_2 = ["John Adams", "male", "2007-06-22", "Matt Damon", "male", "2008-05-19", "Shirley Bassey", "female", "2005-11-02"] </lsl>

When storing data in strided lists, it's often worth it down the road to take a moment at the outset to think about how you are most likely to want to sort them, if ever the need arose. Remember, you can only sort on the first element in each group of elements. If you think you're mostly likely to want to sort on gender (to use the above list example), you should make gender the first element in the data grouping.

Deep Notes

Search JIRA for related Issues

Source

lsa_bubble_sort(): 'linden\indra\lscript\lscript_alloc.h'

Signature

function list llListSort( list src, integer stride, integer ascending );