Difference between revisions of "Talk:Quaternion"
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(Other problem with this page) |
(More precise.) |
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Q' = zQz<sup>-1</sup> | Q' = zQz<sup>-1</sup> | ||
but LSL proceeds in reverse order : | but LSL proceeds in reverse order then it rotates a vector by a rotation (* operator) : | ||
Q' = z<sup>-1</sup>Qz | Q' = z<sup>-1</sup>Qz | ||
Just give a try if you don't believe me... ;-) | Just give a try if you don't believe me... ;-). The reason is LSL follows the right-hand rule | ||
for direction of positive rotations. | |||
This has consequence over the rest of computations. | |||
-- Catherine Pfeffer, 2007-12-06 | -- Catherine Pfeffer, 2007-12-06 | ||
Revision as of 05:32, 7 December 2007
This text says that you rotate a vector Q by a rotation z with the formula :
Q' = zQz-1
but LSL proceeds in reverse order then it rotates a vector by a rotation (* operator) :
Q' = z-1Qz
Just give a try if you don't believe me... ;-). The reason is LSL follows the right-hand rule for direction of positive rotations.
This has consequence over the rest of computations.
-- Catherine Pfeffer, 2007-12-06
This text has two shemas at the end. If you look well at it, the 90° rotation in the first schema and
in the second schema rotate in opposite directions ;-).
It's the second schema that is correct (LSL follows right-hand rule for direction of positive rotations)
-- Catherine Pfeffer, 2007-12-07