Difference between revisions of "User talk:ANSI Soderstrom/Misc useful functions"

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(→‎printf: new section)
Line 13: Line 13:
         list modifiers = ["%s"];
         list modifiers = ["%s"];
         list split = llParseString2List(sentence, [], modifiers);
         list split = llParseString2List(sentence, [], modifiers);
         integer m = llGetListLength(split) - 1;
         integer last = llGetListLength(split) - 1;
         integer i = 0;
         integer i = 0;
         integer k = -1;
         integer k = -1;
         do {
         do {
             while(!~llListFindList(modifiers, llList2List(split, ++k, k))) {
             while(!~llListFindList(modifiers, llList2List(split, ++k, k))) {
                 if(k == m) {//this is an error!
                 if(k == last) {//this is an error!
                     return (string)split;
                     return (string)split;
                 }
                 }

Revision as of 12:13, 14 May 2013


printf

Your printf will have a problem if the text being inserted contains "%s". I'd recommend either splitting the input string into a list or copying the output into a new string so that it doesn't get the opportunity to chew on it's own tail. -- Strife (talk|contribs) 12:10, 14 May 2013 (PDT)

<lsl> // modify a string in ANSI-C style // returns a string with all replacements for "modifier".... based on the equivalent positions in the list-content string printf(string sentence, list insertation) {

   integer j = llGetListLength(insertation);
   if(j) {
       list modifiers = ["%s"];
       list split = llParseString2List(sentence, [], modifiers);
       integer last = llGetListLength(split) - 1;
       integer i = 0;
       integer k = -1;
       do {
           while(!~llListFindList(modifiers, llList2List(split, ++k, k))) {
               if(k == last) {//this is an error!
                   return (string)split;
               }
           }
           //string splitter = llList2String(split, k);
           //if (splitter == "%s")
           split = llListReplaceList(split, llList2List(split, i, i), k, k);
       } while(j > ++i);
       return (string)split;
   }
   return "Error, the insertation list is empty!\n(sentence: " + sentence + ")";

} </lsl>