Talk:Days in Month
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Strife, appreciate the rewriting the code, but you seem to have left out the test for months that are 31 days long. Plz fix.—The preceding unsigned comment was added on 22:42, 2 March 2009 by IntLibber Brautigan
- The current code is already doing that. It's the bit operator portial behind the return.
- (month & 1) gives 1 when it's an uneven month and 0 when it's an even month.
- (month > 7) gives 1 when it's a month after July and 0 otherwise.
- 30 is 11110 in the dual system. So what he does is, he manipulates the last bit with OR and XOR bitwise operators, depending on the month.
- 0|1=1, 0|0=0, 1|1=1, 1^0=1, 1^1=0, 0^0=0
- The code just needed a minor tweak to replace the 6 with a 7.
- This is a pretty clever solution... And it works *just tested*
Lynch (talk|contribs) 23:19, 2 March 2009 (UTC)
