NumberFormat
Revision as of 08:13, 4 May 2007 by Strife Onizuka (talk | contribs) (Strange function but i couldn't resist doing a small optimization (equivalent but faster))
string llNumberFormat(integer)
string llNumberFormat(integer number) { string output; integer x = 0; string numberString = (string)number; integer numberStringLength = llStringLength(numberString); integer z = (numberStringLength + 2) % 3; for(;x < numberStringLength; ++x) { output += llGetSubString(numberString, x, x); if ((x % 3) == z && x != (numberStringLength - 1)) output += ","; } return output; }