NumberFormat

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Revision as of 08:13, 4 May 2007 by Strife Onizuka (talk | contribs) (Strange function but i couldn't resist doing a small optimization (equivalent but faster))
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string llNumberFormat(integer)

string llNumberFormat(integer number)
{
    string output;    
    integer x = 0;
    string numberString = (string)number;
    integer numberStringLength = llStringLength(numberString);
    integer z = (numberStringLength + 2) % 3;
    
    for(;x < numberStringLength; ++x)
    {
        output += llGetSubString(numberString, x, x);
        if ((x % 3) == z && x != (numberStringLength - 1))
            output += ",";
    }
    
    return output;
}