Difference between revisions of "Talk:Quaternion"
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-- Catherine Pfeffer, 2007-12-08 | -- Catherine Pfeffer, 2007-12-08 | ||
:It's probably an artifact of LSL having the operator operands reversed and they forgot to reverse them to match the execution order. For that to make sence you need to know that in most systems when you do (a * b), a is put on the stack before b. In LSO, b is put on the stack before a. If a and b are functions, b is executed before a. Meaning, LSL uses right to left parsing execution. -- [[User:Strife Onizuka|Strife Onizuka]] 08:48, 8 December 2007 (PST) | :It's probably an artifact of LSL having the operator operands reversed and they forgot to reverse them to not match the execution order. For that to make sence you need to know that in most systems when you do (a * b), a is put on the stack before b. In LSO, b is put on the stack before a. If a and b are functions, b is executed before a. Meaning, LSL uses right to left parsing execution. -- [[User:Strife Onizuka|Strife Onizuka]] 08:48, 8 December 2007 (PST) | ||
This text has two shemas at the end. If you look well at it, the 90° rotation in the first schema and | This text has two shemas at the end. If you look well at it, the 90° rotation in the first schema and | ||
Revision as of 09:49, 8 December 2007
In LSL, quaternion multiplication is written down in reverse order as in maths :
Q2 * Q1 (LSL)
is the same as
Q1 . Q2 (maths)
Perharps that would deserve a word of explanation here.
-- Catherine Pfeffer, 2007-12-08
- It's probably an artifact of LSL having the operator operands reversed and they forgot to reverse them to not match the execution order. For that to make sence you need to know that in most systems when you do (a * b), a is put on the stack before b. In LSO, b is put on the stack before a. If a and b are functions, b is executed before a. Meaning, LSL uses right to left parsing execution. -- Strife Onizuka 08:48, 8 December 2007 (PST)
This text has two shemas at the end. If you look well at it, the 90° rotation in the first schema and in the second schema are supposed to be opposite (once in z direction, the other time in -z direction) but the pink arrow materializing the rotation is the same.
It's the first schema that is correct (LSL follows right-hand rule for direction of positive rotations)
-- Catherine Pfeffer, 2007-12-07
- That is correct, LSL uses right-hand rule set. -- Strife Onizuka
- So what do we do to fix this page? (Cathy Pfeffer) [PS my interpretation of z-1Qz problem was wrong, rephrased. See above]