Difference between revisions of "NumberFormat"
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=== ''string'' ''' | {{LSL Header}} | ||
< | |||
string | === ''string'' '''NumberFormat'''(''integer'') === | ||
You can use this to take large numbers and format them to be comma separated by thousands. | |||
<source lang="lsl2"> | |||
string NumberFormat(integer number) | |||
{ | { | ||
string output; | string output; | ||
integer x | integer x = 0; | ||
string numberString = (string)number; | string numberString = (string)number; | ||
integer numberStringLength = llStringLength(numberString); | integer numberStringLength = llStringLength(numberString); | ||
integer z = (numberStringLength + 2) % 3; | |||
for(;x < numberStringLength; ++x) | |||
for( | |||
{ | { | ||
output += llGetSubString(numberString, x, x); | output += llGetSubString(numberString, x, x); | ||
| Line 21: | Line 21: | ||
return output; | return output; | ||
} | } | ||
</ | </source> | ||
{{LSLC|Examples}} | |||
{{#vardefine:sort|NumberFormat}} | |||
Latest revision as of 16:32, 24 January 2015
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string NumberFormat(integer)
You can use this to take large numbers and format them to be comma separated by thousands.
string NumberFormat(integer number)
{
string output;
integer x = 0;
string numberString = (string)number;
integer numberStringLength = llStringLength(numberString);
integer z = (numberStringLength + 2) % 3;
for(;x < numberStringLength; ++x)
{
output += llGetSubString(numberString, x, x);
if ((x % 3) == z && x != (numberStringLength - 1))
output += ",";
}
return output;
}