LSL Operators

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/LSL

Operators are used to cause an operation (or mathematical action) to be performed on one (such as !) or two operands. The easy and common example is 1 + 2 where 1 and 2 are operands, and the + is the operator.

This concept can be extended much further with LSL since operands can be variables with the special case of the assignment operators requiring that the left hand side be a variable.

Operator	Description	Usage Example
() [] .	Parenthesis, Brackets, and Dot	do this second (do this first)
(type)	Typecasting	message = "The result is:" + (string) result;
! ~ ++ --	Binary-NOT, Bitwise-NOT, Increment, Decrement	counter++;
* / %	Multiply/Dot-Product, Divide, Modulus/Cross-Product	rollover = (count + 1)%5;
-	Subtraction	one = 3 - 2;
+	Addition or joining Strings	two = 1+1; text = "Hello" + "World";
+	Concatenation or joining Lists	myList = [1, 2, 3] + [4, 5]; newList = oldList + addList;
<< >>	Left Shift, Right Shift	eight = 4 << 1;
< <= > >=	Less Than, Less Than Or Equal To, Greater Than, Greater Than or Equal To	isFalse = (6 <= 4);
==  !=	Comparison Equal, Comparison Not Equal	isFalse = ("this" == "that");
&	Bitwise AND	zero = 4 & 2; four = 4 & 4;
^	Bitwise XOR	zero = 4 ^ 4; six = 4 ^ 2;
|	Bitwise OR	four = 4 | 4; six = 4 | 2;
||	Comparison OR	isTrue = (FALSE || TRUE);
&&	Comparison AND	isFalse = (FALSE && TRUE);
= += -= *= /= %=	Assignment	four = 4;

Note: Unlike most, if not all, other languages that use the C style && and || operators, both operands are always evaluated. For example,

<lsl>if (TRUE || 1/0) llSay( 0, "Aha!" );</lsl>

will cause a Math Error rather than say "Aha".

Note: The order of precedence of boolean operators is unclear. It is possible that there is a bug in the expression parser, making precedence inconsistent, or it may simply be that || and && have equal precedence; testing is inconclusive. Thus, when in doubt, parenthesize.

Note: The order of evaluation appears to be backwards from most languages. If the value of x starts as 1 then the first two conditions below evaluate false and the second two evaluate true:

<lsl>(x && (x = 0) == 0 && x)</lsl> <lsl>(x && (x = 0) == 0 && x == 0)</lsl> <lsl>(x == 0 && (x = 0) == 0)</lsl> <lsl>(x == 0 && (x = 0) == 0 && x)</lsl>

Both sides are evaluated regardless of the the truth of either side.

+ Operator

result = left + right

Left Type	Right Type	Result Type	Description
integer	integer	integer	Adds left and right
integer	float	float	Adds left and right
float	integer	float	Adds left and right
string	string	string	Concatenates right onto the end of left.
list	*	list	Concatenates right onto the end of left.
*	list	list	Affixes left onto the start of right.
vector	vector	vector	Adds left and right
rotation	rotation	rotation	Adds left and right Not useful for combining rotations, use * or / instead.

Shorthand Operators

Alternatives to the simple '=' operator...

Simple assignment operator	Shorthand operator
a = a + 1	a += 1
a = a – 1	a -= 1
a = a * (n+1)	a *= (n+1)
a = a / (n+1)	a /= (n+1)
a = a % b	a %= b

Bitwise Tips

Equivalencies

AND	OR
~(a & b)	~a | ~b
~a & ~b	~(a | b)
a & ~b	~(~a | b)
~(a & ~b)	~a | b

Code on the left is functionally equivalent to code on the right. a and b need not be variables. In certain circumstances these equivalencies can be used to simplify complex code. I believe this to be an extension of  De Morgan's laws.