Difference between revisions of "ListXneqY"
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Omei Qunhua (talk | contribs) (Yep, examples should compile. Other changes as per ListXequY) |
m (LSL unfortunately does not use short circuiting.) |
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integer ListXneqY(list lx, list ly) | integer ListXneqY(list lx, list ly) | ||
{ | { | ||
if(lx == ly) | |||
return !(ListXnotY(lx,ly) == []); | |||
return FALSE; | |||
} | } | ||
</lsl> | </lsl> | ||
| Line 29: | Line 31: | ||
integer ListXneqY(list lx, list ly) | integer ListXneqY(list lx, list ly) | ||
{ | { | ||
if(lx == ly) | |||
return !(ListXnotY(lx,ly) == []); | |||
return FALSE; | |||
} | } | ||
Revision as of 08:50, 21 April 2014
| LSL Portal | Functions | Events | Types | Operators | Constants | Flow Control | Script Library | Categorized Library | Tutorials |
Function: integer ListXneqY(list lx, list ly);
Answers the question: is list X different from list Y?
Returns the number 1 if true, 0 if false
Note: requires also the function ListXnotY .
The opposite function is ListXequY .
See also: Lists
<lsl> integer ListXneqY(list lx, list ly) {
if(lx == ly)
return !(ListXnotY(lx,ly) == []);
return FALSE;
} </lsl>
Example:
<lsl> list l1 = ["a","b","c","d", 1,2]; list l2 = ["a",1,"b",2,"c",3,"d"];
integer ListXneqY(list lx, list ly) {
if(lx == ly)
return !(ListXnotY(lx,ly) == []);
return FALSE;
}
list ListXnotY(list lx, list ly) {// return elements in X list that are not in Y list
list lz; integer n = llGetListLength(lx); while(n--)
if ( !~llListFindList(ly,llList2List(lx,n,n)) ) lz += llList2List(lx,n,n);
return lz;
}
default{
state_entry() {
llSay(0, "Are we different lists? " + (string)ListXneqY(l1,l2));
//will say in this example: 1 , meaning yes.
}
} </lsl>
Posted with the kind permission of Very Keynes, who originated this script June 2007 in the SL scripters forum http://forums-archive.secondlife.com/54/e4/194138/1.html