Difference between revisions of "ListXneqY"
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See also: [[List|Lists]] | See also: [[List|Lists]] | ||
< | <source lang="lsl2"> | ||
integer ListXneqY(list lx, list ly) | integer ListXneqY(list lx, list ly) | ||
{ | { | ||
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return TRUE; | return TRUE; | ||
} | } | ||
</ | </source> | ||
Example:<br /> | Example:<br /> | ||
< | <source lang="lsl2"> | ||
list l1 = ["a","b","c","d", 1,2]; | list l1 = ["a","b","c","d", 1,2]; | ||
list l2 = ["a",1,"b",2,"c",3,"d"]; | list l2 = ["a",1,"b",2,"c",3,"d"]; | ||
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} | } | ||
} | } | ||
</ | </source> | ||
</div> | </div> | ||
Latest revision as of 14:24, 22 January 2015
| LSL Portal | Functions | Events | Types | Operators | Constants | Flow Control | Script Library | Categorized Library | Tutorials |
Function: integer ListXneqY(list lx, list ly);
Answers the question: is list X different from list Y?
Returns the number 1 if true, 0 if false
Note: requires also the function ListXnotY .
The opposite function is ListXequY .
See also: Lists
integer ListXneqY(list lx, list ly)
{
if(lx == ly)
return !(ListXnotY(lx,ly) == []);
return TRUE;
}
Example:
list l1 = ["a","b","c","d", 1,2];
list l2 = ["a",1,"b",2,"c",3,"d"];
integer ListXneqY(list lx, list ly)
{
if(lx == ly)
return !(ListXnotY(lx,ly) == []);
return FALSE;
}
list ListXnotY(list lx, list ly)
{// return elements in X list that are not in Y list
list lz;
integer n = llGetListLength(lx);
while(n--)
if ( !~llListFindList(ly,llList2List(lx,n,n)) )
lz += llList2List(lx,n,n);
return lz;
}
default{
state_entry() {
llSay(0, "Are we different lists? " + (string)ListXneqY(l1,l2));
//will say in this example: 1 , meaning yes.
}
}
Posted with the kind permission of Very Keynes, who originated this script June 2007 in the SL scripters forum http://forums-archive.secondlife.com/54/e4/194138/1.html