User:Dora Gustafson/occurences
< User:Dora Gustafson
Jump to navigation
Jump to search
Revision as of 02:19, 2 April 2014 by Dora Gustafson (talk | contribs) (→Count Occurrences in a list)
Count Occurrences in a list
Look for and count anything, that can be an element, in a list
- This script is an example which include a list: "haystack" and an element: "needle"
- Here "haystack" and "needle" are constants and only meant to make up a working script
<lsl> // count occurrences in list; by Dora Gustafson, Studio Dora 2014 // v1.1 inline code
default {
state_entry() { list haystack = [1,2,1,2,1,2,3,2,4,5,2,6,4,2,3,2,1,8]; list needle = [2]; integer i = 0; integer j = 0; integer k = llListFindList( haystack, needle); integer m = llGetListLength( haystack ); while ( k >= 0 && i < m ) { i += k+1; k = llListFindList( llList2List( haystack, i, -1), needle); ++j; } llOwnerSay((string)needle+" occurs "+(string)j+" times in "+llDumpList2String( haystack, ", ")); }
} </lsl> This program is straight, a recursive approach follows <lsl> // count occurrences in list; by Dora Gustafson, Studio Dora 2014 // v1.1 inline code // v1.2 recursive approach
list haystack = [1,2,1,2,1,2,3,2,4,5,2,6,4,2,3,2,1,8]; list needle = [2]; integer j = 0;
tin( list L ) {
integer k = llListFindList( L, needle); if ( k >= 0 ) { ++j; if ( k+1 < llGetListLength(L) ) tin( llList2List( L, k+1, -1)); }
}
default {
state_entry() { tin( haystack); llOwnerSay((string)needle+" occurs "+(string)j+" times in "+llDumpList2String( haystack, ", ")); }
}</lsl>
The advantage of recursion over straight code is a shorter code(the code is reused)
The disadvantages are longer execution time and more overhead generated at runtime
- For these reasons the recursion approach is a bad choice to search a long list in LSL