Category talk:LSL Avatar/Name
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Presumably, if one checks the size of the list created in the LegacyToUsername function, then it can cope with being given a username or a legacy name and still return the correct string?
i.e. the following ...
<lsl>string LegacyToUsername(string legacy) {
list name = llParseString2List(llToLower(legacy), [" "],[]); if (llGetListLength(name) == 1)//no spaces, so is already a username return llList2String(name, 0);//string is already a username if(llList2String(name, 1) == "resident")//it's not a legacy account. return llList2String(name, 0);//first name is username return llDumpList2String(name, ".");
}</lsl>
Kimm Paulino 13:49, 14 March 2011 (PDT)