Difference between revisions of "Right Shift"
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// output should be 268435449 | // output should be 268435449 | ||
llSay(DEBUG_CHANNEL, (string)rightShift(-99, 4)); // output :-7 | llSay(DEBUG_CHANNEL, (string)rightShift(-99, 4)); // output :-7 | ||
llSay(DEBUG_CHANNEL, (string) | llSay(DEBUG_CHANNEL, (string)rightShiftCorrect(-99, 4)); // output : 268435449 | ||
// before: 1111 1111 1111 1111 1111 1111 1001 1101 | // before: 1111 1111 1111 1111 1111 1111 1001 1101 | ||
// after: 0000 1111 1111 1111 1111 1111 1111 1001 | // after: 0000 1111 1111 1111 1111 1111 1111 1001 |
Revision as of 07:08, 20 November 2011
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Unsigned vs. Arithmetic
There are two types of Right Shifts, that can be performed on an integer. They are: Unsigned and Arithmetic. LSL currently only supports Arithmetic. The difference between the two modes is how it fills the bits revealed. With the unsigned mode, the revealed bits are always zero; in Arithmetic mode, it duplicates the old top bit to all the new bits. If you take the expression value >> count
where value is arithmetically shifted right count bits, then this is the same mathematically as doing value / (2count)
or in LSL value / llPow(2.0, count)
.
How to do Unsigned Right Shifts in LSL
Since LSL does not have a unsigned right shift operator you have to do it yourself. There are two methods for doing this, each with it's advantages and disadvantages.
There is a feature suggestion to add an unsigned right shift operator to LSL: SVC-1171
Method 1
<lsl>(value >> count) & ~((~value) >> count);</lsl> This method is good when count is dynamic. It works because all the bits that need to be turned on will be turned on both sides of the AND but on only one side will the arithmetic right shift cause the sign bit to be extended. The result of the and is a value that is always a unsigned right shift.
The method above doesn't work.
<lsl> // Jonhboy Resident
integer rightShift(integer value, integer count) {
if(count%32) return ~(0x80000000 >> --count) & (value >> count); return value;
}</lsl>
Method 2
<lsl>(value >> count) & mask;</lsl>
This method can only be used when count is a constant value. You use a constant mask to remove the extended sign bits. Example: (value >> 5) & 0x07FFFFFF
As you can see the top five bits have been turned off in the mask value, if you have trouble seeing that, you can just use the lookup table below.
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Example Unsigned Right Shift Function
Here's a function that encapsulates the first method. It allows for a signed 32 bit integer along with a value indicating how far to shift the bits to be executed as an unsigned right shift.
<lsl>// the lsl right shift is an arithmetic right shift, // this means it more closely resembles dividing by a // positive power of two then a unsigned right shift. // To perform a unsigned right shift you need to be clever integer rightShift(integer value, integer count) {
return (value >> count) & ~((~value) >> count); //This works because only once side of the '&' operation //Has the sign bit extended by the arithmetic right shift //The purpose of flipping of the bits on the right side //ensures this, the subsequent '&' removes the extended //sign bits.
// Jonhboy Resident
integer rightShiftCorrect(integer value, integer count) {
if(count%32) return ~(0x80000000 >> --count) & (value >> count); return value;
}
}</lsl> Example Usage: <lsl>default {
state_entry() {
// output should be 268435449 llSay(DEBUG_CHANNEL, (string)rightShift(-99, 4)); // output :-7 llSay(DEBUG_CHANNEL, (string)rightShiftCorrect(-99, 4)); // output : 268435449 // before: 1111 1111 1111 1111 1111 1111 1001 1101 // after: 0000 1111 1111 1111 1111 1111 1111 1001 }
}</lsl>