Difference between revisions of "Merge Sort"

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m
(Changed code to be in <lsl>.)
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I realize I shouldn't be using iteration in a recursive method... Sue me.
I realize I shouldn't be using iteration in a recursive method... Sue me.


<pre>
<lsl>
list sort(list l) {
list sort(list l) {
     if (llGetListLength(l) > 1) {
     if (llGetListLength(l) > 1) {
Line 45: Line 45:
     return ret;
     return ret;
}
}
</pre>
</lsl>





Revision as of 10:34, 8 February 2008

Created by Xaviar Czervik. Do whatever you wish with this function: Sell it (good luck), use it, or modify it.

This code sorts a list through use of a Merge Sort. I have no idea why you would want to use it as it is more than 150 times slower than llListSort(), but it is a good demonstration of how a Merge Sort works.

I realize I shouldn't be using iteration in a recursive method... Sue me.

<lsl> list sort(list l) {

   if (llGetListLength(l) > 1) {
       integer mid = llGetListLength(l)/2;
       list l2 = sort(llList2List(l, 0, mid-1));
       list l3 = sort(llList2List(l, mid, -1));
       return merge(l2, l3);
   }
   return l;

}

list merge(list l, list r) {

   integer lm = llGetListLength(l);
   integer rm = llGetListLength(r);
   integer lc;
   integer rc;
   list ret;
   while (lc < lm || rc < rm) {
       if (lc >= lm) {
           ret += llList2Integer(r, rc);
           rc++;
       } else if (rc >= rm) {
           ret += llList2Integer(l, lc);
           lc++;
       } else {
           if (llList2Integer(l, lc) <= llList2Integer(r, rc)) {
               ret += llList2Integer(l, lc);
               if (lc < lm)
                   lc++;
           } else {
               ret += llList2Integer(r, rc);
               if (rc < rm)
                   rc++;
           }
       }
   }
   return ret;

} </lsl>