Difference between revisions of "SubStringLastIndex"

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m (+recursion warning)
(normally i disapprove of such shenanigans, but then I also disapprove of using recursion, so it's moot. This should keep the heap from ballooning as quickly (which will help in LSO but not in Mono))
Line 44: Line 44:
     integer index2;
     integer index2;
     if (index != -1) //found, look again
     if (index != -1) //found, look again
         index2 = uSubStringLastIndex(llGetSubString(vStrSrc, index + 1, -1), vStrTst) + 1;
         index2 = uSubStringLastIndex(llGetSubString(vStrSrc, index + 1, -1), (vStrSrc = vStrTst = "") + vStrTst) + 1;
     return index + index2;
     return index + index2;
}
}

Revision as of 22:18, 23 March 2012

User-Defined Function: integer uSubStringLastIndex( string vStrSrc, string vStrTst );

Returns a integer that is the positive index of the last vStrTst within vStrSrc

  • vStrSrc: source string to check
  • vStrTst: string to look for

if vStrTst is not found in vStrSrc -1 is returned.
the index of the first character is 0


Code:

  • LSO: 182 bytes
  • MONO: 1024 bytes

<lsl>integer uSubStringLastIndex( string vStrSrc, string vStrTst ){

   integer vIdxFnd =
     llStringLength( vStrSrc ) -
     llStringLength( vStrTst ) -
     llStringLength(
       llList2String(
         llParseStringKeepNulls( vStrSrc, (list)vStrTst, [] ),
         0xFFFFFFFF ) //-- (-1)
       );
return (vIdxFnd

Caveats

  • Performs a literal match (case sensitive).
    • Wildcards and RegEx are not supported.
  • Attempting to match an empty string ("") will return 0 instead of -1.

Notes

  • This function is operates exactly like llSubStringIndex (including caveats), from the opposite end of the string.