SubStringLastIndex
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User-Defined Function: integer uSubStringLastIndex( string vStrSrc, string vStrTst );
Returns a integer that is the positive index of the last vStrTst within vStrSrc
- vStrSrc: source string to check
- vStrTst: string to look for
if vStrTst is not found in vStrSrc -1 is returned.
the index of the first character is 0
Code:
- LSO: 182 bytes
- MONO: 1024 bytes
integer uSubStringLastIndex( string vStrSrc, string vStrTst ){
integer vIdxFnd =
llStringLength( vStrSrc ) -
llStringLength( vStrTst ) -
llStringLength(
llList2String(
llParseStringKeepNulls( vStrSrc, (list)vStrTst, [] ),
0xFFFFFFFF ) //-- (-1)
);
return (vIdxFnd | (vIdxFnd >> 31));
}
/*//-- Anti-License Text --//*/
/*// Contributed Freely to the Public Domain without limitation. //*/
/*// 2009 (CC0) [ http://creativecommons.org/publicdomain/zero/1.0 ] //*/
/*// Void Singer [ https://wiki.secondlife.com/wiki/User:Void_Singer ] //*/
/*//-- --//*/
Code:
Alternative implementation - may be faster, tested.
(warning: uses recursion, high potential for LSL stack heap collision when processing large and/or highly repetitive strings)
integer uSubStringLastIndex(string vStrSrc, string vStrTst)
{
if (vStrTst == "")
return 0;
integer index = llSubStringIndex(vStrSrc, vStrTst);
integer index2;
if (index != -1) //found, look again
index2 = uSubStringLastIndex(llGetSubString(vStrSrc, index + 1, -1), vStrTst) + 1;
return index + index2;
}
/*// Contributed Freely to the Public Domain without limitation by Sasun Steinbeck. //*/
Third solution, tested
integer uSubStringLastIndex(string hay, string pin)
{
integer index2 = -1;
integer index;
if (pin == "")
return 0;
while (~index)
{
index = llSubStringIndex( llGetSubString(hay, ++index2, -1), pin);
index2 += index;
}
return index2;
}
Caveats
- Performs a literal match (case sensitive).
- Wildcards and RegEx are not supported.
- Attempting to match an empty string ("") will return 0 instead of -1.
Notes
- This function is operates exactly like llSubStringIndex (including caveats), from the opposite end of the string.