Difference between revisions of "LlLog10"
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|examples=< | |examples=<source lang="lsl2">default | ||
{ | { | ||
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llOwnerSay("The base 10 logarithm of " + (string)num1 + " is " + (string)llLog10(num1)); | llOwnerSay("The base 10 logarithm of " + (string)num1 + " is " + (string)llLog10(num1)); | ||
} | } | ||
}</ | }</source> | ||
|helpers | |helpers | ||
|also_functions={{LSL DefineRow||[[llLog]]|}} | |also_functions={{LSL DefineRow||[[llLog]]|}} | ||
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|also_articles={{LSL DefineRow||{{Wikipedia|Logarithm}}|}} | |also_articles={{LSL DefineRow||{{Wikipedia|Logarithm}}|}} | ||
|notes=There are only two log functions [[llLog]] and [[llLog10]]. Errors introduced as a result of floating-point arithmetic are most noticable when working with logarithms. [[llLog]] should be used instead of [[llLog10]] when converting the base of the logarithm. | |notes=There are only two log functions [[llLog]] and [[llLog10]]. Errors introduced as a result of floating-point arithmetic are most noticable when working with logarithms. [[llLog]] should be used instead of [[llLog10]] when converting the base of the logarithm. | ||
< | <source lang="lsl2">float LogBaseN = llLog(value) / llLog(Base); //This technique introduces errors but is the only way</source> | ||
|permission | |permission | ||
|negative_index | |negative_index |
Latest revision as of 12:20, 22 January 2015
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Summary
Function: float llLog10( float val );264 | Function ID |
0.0 | Forced Delay |
10.0 | Energy |
Returns a float that is the base 10 logarithm of val.
If val <= 0 return zero instead.
• float | val |
To get the natural logarithm use llLog.
llLog10 should only be used where the base 10 log is needed, all other applications should use llLog instead.
Caveats
Examples
default
{
state_entry()
{
float num1 = llFrand(100.0);
llOwnerSay("The base 10 logarithm of " + (string)num1 + " is " + (string)llLog10(num1));
}
}
Notes
There are only two log functions llLog and llLog10. Errors introduced as a result of floating-point arithmetic are most noticable when working with logarithms. llLog should be used instead of llLog10 when converting the base of the logarithm.
float LogBaseN = llLog(value) / llLog(Base); //This technique introduces errors but is the only way